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10/11/24 Lab 3. Hydrated Compounds Purpose: To use hydrated compounds to practice calculating how much water molecules are attached to other molecules and compounds. Procedure: Clean the crucible with water, dry it with a paper towel, and heat it fo...

Mass of crucible and hydrated compound: 16.08g Mass of crucible and anhydrous compound(first heating): 14.55g Mass of crucible and anhydrous compound(second heating): 14.55g Observations: The MgSO4•xH2O turned a more white color and seemed to melt into a s...

10/14/24 I get a ratio of 1:9.6 mol MgSO4:H2O, the correct ratio is 1:7. My results are pretty accurate. The water must have been pretty close to completely evaporated, assuming the scale was 100% accurate. The error most likely comes from an inaccurate scale...

10/15/24 Partner: Connor Engels Lab 4. Empirical Formula Determination Purpose: To determine the empirical formula for a tin-oxygenated product. Procedure: Clean and dry an evaporating dish and a watch glass cover. To dry them, heat strongly for 2-...

Data: Mass of tin: 2g Mass of tin, evaporating dish, and watching glass: 39.21g Mass after 1st heating: 39.76g Mass after 2nd heating: 39.71g Mass after 3rd heating: 39.71g Observations: It started to bubble, turn orange, and let off orange vapor. Bad, ...

10/16/24 Analysis: Mass of Sn 2.00 g/118.7 g/mol=0.0168 mol Sn 39.71g-39.21g=0.5g O mass O 0.5 g/16.00 g/mol=0.0313 mol O 0.0313 mol O/0.0168 mol Sn=1.86≈2 O 0.0168 Sn/0.0168 Sn=1 Sn Empirical Formula=SnO2 Conclusion: The purpose of the lab was to det...

Partner: Jeff Somvorachith 10/31/24 Lab 5. Reactions in Solution Precipitation Purpose: To practice identifying reactions that result in precipitation and practice recognizing and writing equations for double replacement reactions by testing pairs of reage...

solutions to the proper location. Some of the solutions contain transition metal ions, so should not be washed down the drain. Instead, dump the contents onto a paper towel in the tray labeled "transition metal waste". Wash some items with water and clean othe...

Conclusion: a. Formula of Precipitates CoCl2 CuCl2 AlCl3 BaCl2 NiCl2 NaI CuI2 Na2CO3 CoCO3 CuCO3 Al2(CO3)3 BaCO3 NiCO3 Na3PO4 Co3(PO4)2 Cu3(PO4)2 AlPO4 Ba3(PO4)2 Ni3(PO4)2 Na2SO4 BaSO4 NaOH...

11/1/24 c. Net ionic formulas Cu2++2I+->CuI2  Co2++Co32-->CoCO3 Cu2++Co32+->CoCO3 2Al3++3CO32-->Al2(CO3)3 Ba2++CO32-->BaCO3 Ni2++CO32-->NiCO3 3Co2++2PO43-->Co3(PO4)2 3Cu2++2PO43-->Cu3(PO4)2 Al3++PO43-->AlPO4 3Ba2++2PO43-->Ba3(PO4)2 3Ni2++2PO43-->Ni...

Partner: Jeff Somvorachith 11/4/24 6. Stoichiometry and Limiting Reagent Purpose: To practice using stoichiometry and identifying and calculating the limiting reagent by reacting copper(II) sulfate with iron, determining the limiting reagent, and observing...

The tape on our beaker burned. Took about 1 minute 50 seconds to dissolve. Letting off steam. Seems to heat up more when adding the iron. Solution turned from blue to grey. Iron seemed to rust. Combined to form Fe3O3. Has an iron sort of smell. Precipitate set...

3. Water was added to remove any underacted copper(II) sulfate, iron, and iron(II) sulfate. The solution was washed to isolate the copper. 4. The water added didn't matter if the measurement w for water was exact because it wasn't included in the reaction. Wa...

was left over after and what was left over was the limiting reactant. The limiting reactant turned out to be the iron, both through math and observations, as copper was all that was left after. All of the iron would have reacted to form iron(II) sulfate, leavi...

11/7/24 Partner: Jeff Somvorachith 7. Standardization of a NaOH Solution Purpose: To determine the molarity of an NaOH solution by reacting a kniwn volume of each reagent, NaOH and KHP, and using the known molarity of the KHP solution to determine the mola...

7. Calculate the percent deviation between the trials. % deviation=(highest molarity - lowest molarity)/average molrity *100 8. If the % deviation is greater than 5%, repeat the titration process. Data: Trial 1 Trial 2 Trial 3 Trial 4 Trial 5 ...

Analysis:   KHC8H4O4+NaOH->NaKC8H4O4+H2O Trial 1: 10.00mL-0.20mL=9.80mL NaOH used 2.00g/(39.10+1.008+8*12.01+4*1.008+4*10.00)*(1/1)*(9.80/1000)=0.999~1.0M Trial 2: 19.70mL-10.00mL=9.70mL NaOH used 2.00g/(39.10+1.008+8*12.01+4*1.008+4*10.00)*(1/1)*(9.70/1...

Our % deviation was 0.990%, meaning our answers between each trial was pretty close to the average. Since we got one really good titration, the % deviation means we were really close to being exact and getting a light pink color, within a few hundreths of a mi...